# Classic Puzzles

## Wednesday, December 20, 2006

### Microsoft Puzzle : Coins on the Table

This is not one of the classic Microsoft puzzle. I recently heard from a friend. I am listing the problem below.

There is a table on which a number of coins are placed. You also know that there are as many coins with Head up as many coins with Tail up. Now you have to divide the coins (number of coins is even) into two equal piles such that number of coins with Heads up and Tails up in either piles be the same. The catch is you are blind folded and you cannot determine the sides (for sure) if you are blinded

pai said...

Simple- Divide the coins in half by quantity (easy to count coins while blindfolded)

Then, flip all the coins in one pile over.

Satyan Raina said...

I don't think this works

Consider this distribution after making two piles
___________
___|_1_|_2_|
_H_|35_|_30|
_T_|15_|_20|

after flipping second pile

___________
___|_1_|_2_|
_H_|35_|_20|
_T_|15_|_30|

jedifreac said...

Logical Warrior, the question actually tells you "You also know that there are as many coins with Head up as many coins with Tail up." so the scenario you've posited doesn't match (you have 65 heads and 35 tails)

xxxxxxxxxx said...

It doesn't make sense to simply divide in half and flip one pile. Suppose you divide it such that all Hs are in one pile and all Ts in the other. You end up with all Hs or all Ts.

xxxxxxxxxx said...

I think you can compare two coins (without knowing it is H or T) to know if they are the same or different. By this means you can simply count and collect the same type of coins.

JohnSchroder said...

shhh:
yes but that is ok. The requirement is that in the end the # of Tails in pile 1 equals the # of tails in pile 2 and the same with heads.
if they are all tails or all heads that is just fine.

Anonymous said...

nice puzzle, its interesting. you can check my coin collecting
directory. you will like it too.

Shreyas Mahajan said...
This comment has been removed by the author.
Shreyas Mahajan said...
This comment has been removed by the author.
Arvind said...

no. of tails T (40)

put smaller(T,H) coins at random in pile1 (40). (25 H , 15 T)

fill the pile2 (50 coins) using remaining coins.(27 H ,23 T)

invert all the remaining coins
( 8 H, 2 T) --> (2 H, 8 T)

put these coins in pile1.(27 H ,23 T)

Sinclair Calleja said...

Why complicate matters? Pai was right - simly divide the coins by half and flip one pile over. If you need convincing, here's the logic:

Consider we have x heads and x tails (amounts are equal - given). Take any random x coins consisting of n heads ( 0 <= n <= x) and x-n tails. Automatically, second pile will contain x-n heads and n tails. By swapping heads with tails in second pile, we end up with n heads and x-n tails in the second pile as well...

Maverick said...

Assume you have N heads and N tails coins initially.

u make two piles out of them by taking m Tails and s Heads. he second pile will have N-m Tails + N-s Heads

since the two piles are equal :-

m+s = N-m + N-s
i.e. m+s = N

So we have as many heads in pile one as we have tails in pile two.

So just flip.

So

Unknown said...

power balance
silly bandz
Raymond Weil Watches
concord papillon
rolex datejust 36mm
wedding dresses develop quality for discerning customers and Experience the comfort, free shipping.
Buy evening dresses with a price guarantee and top rated customer service.

Maria said...

Logical Warrior, the question actually tells you "You also know that there are as many coins with Head up as many coins with Tail up." so the scenario you've posited doesn't match (you have 65 heads and 35 tails.
cheap perfume
Burberrys perfume
dolce & gabbana perfume
Estee lauder sensuous perfume
euphoria perfume
guess perfume

For more interview puzzles check techinterviewpuzzles.com

Unknown said...

I think that people are taking it as number of heads and tails in a single tile is same, but that is wrong the correct interpretation would be that heads in one pie is same as heads in other pile and same for tails. Now it is simple isn't it?

DomoMaster said...

Your puzzle is quite challenging. I can't figure it out.

Caro
sudoku

lavesh said...

Hi I got inspired by your blog and created my own puzzle blog
Logic puzzles

Anonymous said...

I would put them all on their edge. This way both piles have zero head/tail up.

joanne said...

I don't mean to be sound stupid if this isn't the correct answer, but I was able to figure this out in less than a minute. Can't you just feel for it by using your finger along the edges? Clearly the heads will have a silhouette feeling for a face vs. a tail. So you can use your finger to fix it. So what I would do is take one coin and put it in my left hand. This will be my "Control" coin. With my right hand, I will put the "Test" coin next to the "Control" coin and with my index finger, compare the feeling of the ridges to the "Control." If it feels the same, then I'll put in in the pile I'll create to the right. If it feels different, then I'll put it in a pile to the left.

ajay kumar said...

just pick half of coins in one and remaining half in 2nd pile.

and then reverse all coins of 2nd pile. THATS IT.

EXAMPLE..think u have 30 heads and 30 tails initially..after picking them in both piles
I II
H x (30-x)
T (30-x) x

becoz if 1st pile has x heads then it should have 30-x as tails as total is 30..
thanks
Kumar_ajay

Ammar Mohemmed said...

for those proposing to divide into two halves then flipping , that will be true if the u are not blind , means the fold was removed , right ?

Hari said...

Remove all the coins from the table. Tell that you have created two empty sets with zero heads and zero tails in each set ;)

Hari said...

Remove all the coins from the table. Tell that you have created two empty sets with zero heads and zero tails in each set ;)

Unknown said...

PILE EXTERNAL (HEAMOROID) is a very common problem for a very long time, and the medication to the cure is available by contacting Dr Benard on benardleo13@gmail.com or on +2349027116105 I got his number from the net.he was the Doctor who helped me out.

Anand K said...

As an algorithm, here is what I would do:
1. Pick any coin at random from the first table
2. Place it as is on the second table.
3. Pick the second coin at random from the first table
4. Place it as flipped on the second table
5. Repeat steps 1 through 4 until all coins are placed on second table.

Unknown said...

Easy. Just feel the coins and put them in piles.

Unknown said...

Am very happy saying this.
My son once suffered from the problem of pile,he was having
Anal Fissure, Anal Itching.
Blood in the Stool (Rectal Bleeding), Constipation,Diarrhea, Hemorrhoids Quiz and also
Laxatives For Constipation. I got a permanent cure to it from Dr Alegbe he gave me his herbal product which i used on him. now my son is living fine and normal. any body with such problem can contact him on +2349027116105 or mail him on alegbejohn7@gmail.com

Susan said...

Thanks so much for this information. I have to let you know I concur on several of the points you make here and others may require some further review, but I can see your viewpoint. Save yourself the hassle and use this Instagram online viewer instead. ... Deskgram is a desktop app which allows you to post, comment, like, and browse your photos ...